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Detect if function was called with "then"

I'm making my own ajax function like jQuery and this is what I have so far

const ajax = function(options){
    const defaults = {
        type: 'GET',
        url: window.location,
        data: {},
        success: function(){},
        error: function(){}
    },
    opts = {...defaults, ...options};

    const xhr = new XMLHttpRequest();
    xhr.addEventListener("load", function(){
        opts.success.call(this, xhr.response, xhr);
    });
    xhr.addEventListener("error", function(){
        opts.error.call(this, xhr);
    });
    xhr.open(opts.type, opts.url);
    xhr.send();
}

and I can call it like

ajax({
    success: (data) => {
        console.log(data);
    }
});

It works. But I want to add optional promise to it. So I want to be able to call this function exactly like this but also like

ajax().then(data => {
    console.log(data);
}).catch(error => {
    console.log(error);
});

I'm new to promises so I'm not sure how to modify the function such that I can detect whether to resolve/reject or call callbacks. Also am I doing something that is considered bad practice?

const ajax = function(options){
    const defaults = {
        type: 'GET',
        url: window.location,
        data: {},
        success: function(){},
        error: function(){}
    },
    opts = {...defaults, ...options};

    return new Promise((resolve, reject) => {
        const xhr = new XMLHttpRequest();
        xhr.addEventListener("load", function(){
            resolve(xhr.response);
        });
        xhr.addEventListener("error", function(){
            reject(xhr);
        });
        xhr.open(opts.type, opts.url);
        xhr.send();
    });
}
about 4 years ago · Juan Pablo Isaza
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